tmermima7nnagal
Answered

The molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?

Verified Answer :

MissPhiladelphia

The chemical reaction would be as follows:
2LiOH + CO2 = Li2CO3 + H2O

We are given the amount of the CO2 to be used in the reaction. We use this to calculate the amount of LiOH. We do as follows:

25.5 g CO2 ( 1 mol / 44.01 g ) ( 2 mol LiOH/1 mol CO2)  = 1.16 mol LiOH needed

Answer : The moles of \(LiOH\) needed are, 1.158 moles

Explanation : Given,

Mass of \(CO_2\) = 25.5 g

Molar mass of \(CO_2\) = 44.01 g/mole

First we have to calculate the moles of \(CO_2\).

\(\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}=\frac{25.5g}{44.01g/mole}=0.579moles\)

Now we have to calculate the moles of \(LiOH\)

The balanced chemical reaction will be,

\(2LiOH+CO_2\rightarrow Li_2CO_3+H_2O\)

From the balanced chemical reaction we conclude that,

As, 1 mole of \(CO_2\) react with 2 moles of \(LiOH\)

So, 0.579 mole of \(CO_2\) react with \(2\times 0.579=1.158\) moles of \(LiOH\)

Therefore, the moles of \(LiOH\) needed are, 1.158 moles

Related Questions