Luciemobabeller
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  1. Graph the six terms of a finite series where a1 = 5 and r = 1.25.

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MissPhiladelphia

For the answer to the question above, asking to graph the six terms of a finite series where a1 = 5 and r = 1.25.
I'll provide the answer with the solutions below.
a1 = 5 
a2 = 5r = 5(5/4) = 25/4 
a3 = 5r² = 5(5/4)² = 125/16 
a4 = 5r³ = 5(5/4)³ = 625/256 
a5 = 5r⁴ = 5(5/4)⁴ = 3125/1024
I hope this helps

adioabiola

The six terms of a finite series where a1 = 5 and r = 1.25 are;

  • a(2) = a1 × (1.25)^(2-1) = 6.25
  • a(3) = a1 × (1.25)^(3-1) = 7.8125
  • a(4) = a1 × (1.25)^(4-1) = 9.7656
  • a(5) = a1 × (1.25)^(5-1) = 12.2070
  • a(6) = a1 × (1.25)^(6-1) = 15.2588

Terms of finite series

According to the question;

  • The first term of the series is; 5
  • The common ratio of the series is; 1.25 = (5/4)

The terms of the series can be obtained from the general formula;

  • a(n) = a1 × (1.25)^(n-1)

The terms are as follows;

  • a(2) = a1 × (1.25)^(2-1) = 6.25
  • a(3) = a1 × (1.25)^(3-1) = 7.8125
  • a(4) = a1 × (1.25)^(4-1) = 9.7656
  • a(5) = a1 × (1.25)^(5-1) = 12.2070
  • a(6) = a1 × (1.25)^(6-1) = 15.2588

Read more on terms of a finite series;

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