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What is the standard form of (1 7i)(3 − i)?(-10 − 10i)(-4 − 10i)(10 20i)(20 10i)

Verified Answer :

TheBlueLight

10 +20i you just multiply and look what to write simply

Answer:

Standard form of (1 +7i)(3 − i) is:

10+20i

Step-by-step explanation:

We have to multiply (1+7i) and (3-i)

(1+7i)(3-i)=1(3-i)+7i(3-i)

             = 3-i+21i-7i²

            =3+20i+7  (since, i²= -1)

           =10+20i

Hence, standard form of (1 +7i)(3 − i) is:

10+20i

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