Sodium sulfate reacts with carbon to produce the products sodium sulfide and carbon monoxide. Identify the reducing agent in the following reaction.

Na2SO4 + 4C yields Na2S + 4CO


Na2SO4

C

Na2S

CO

Verified Answer :

The reducing agent will itself be oxidized.
The oxidation number of carbon goes form 0 to +2. Therefore, it is the reducing agent.

Answer : The correct option is, carbon (C)

Explanation :

Oxidizing agent : Oxidizing agent are the agent that gains electrons and is reduced in a chemical reaction.

Reducing agent : Reducing agent are the agent that lose electrons and is oxidized in a chemical reaction.

The given balanced chemical reaction is,

\(Na_2SO_4+4C\rightarrow Na_2S+4CO\)

First we have to calculate the oxidation number of sulfur and carbon.

The oxidation state of 'S' in \(Na_2SO_4\) and \(Na_2S\) are, (+6) and (-2) respectively.

The oxidation state of 'C' in \(4C\) and \(4CO\) are, (0) and (+2) respectively.

From this we conclude that, the \(Na_2SO_4\) act as an oxidizing agent and 'C' act as a reducing agent.

Hence, the reducing agent in the following reaction is, carbon (C)