jarsammiDlaforette
Answered

How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?

6Li + N₂ 2Li₃N


0.013 moles


0.04 moles


0.08 moles


0.16 moles


0.48 moles

Verified Answer :

scme1702

Each mole of N₂ generates 2 moles of Li₃N. Thus,
0.08 moles of Li₃N will require:
0.08 / 2
= 0.04 moles of N₂

The second option is correct.

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