Answer:
3.43 m
Explanation:
For maximum distance that is maximum range of a projectile, the angle of projectile should be 45°.
The formula for range is:
\(R = \frac{u^2 sin 2\theta}{g}\)
where, u is the initial velocity, θ is the angle of projectile and g is the acceleration due to gravity.
Substitute the values, u = 5.80 m/s, θ = 45° and g = 9.81 m/s²
\(R = \frac{5.80^2\times sin 90^o}{9.81} = 3.43 m\)
