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Fernando612 Fernando612
  • 25-03-2014
  • Mathematics
Answered

Compute without using a calculator.

sin (9π/4)tan(7π/3)

Verified Answer :

Anonymous Anonymous
  • 28-03-2014

\(sin\left(\frac{9\pi}{4}\right)tan\left(\frac{7\pi}{3}\right)=sin\left(2\frac{1}{4}\pi\right)tan\left(2\frac{1}{3}\pi\right)=sin\left(2\pi+\frac{1}{4}\pi\right)tan\left(2\pi+\frac{1}{3}\pi\right)\\\\=sin\frac{1}{4}\pi tan\frac{1}{3}\pi=\frac{\sqrt2}{2}\cdot\sqrt3=\frac{\sqrt6}{2}\)

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