Which of the following shows a number as a product of prime numbers in exponential form? Choose all that apply. 5^2 7 13 7^2 24 3^2 13 4 * 5^3
A and C, because prime numbers are numbers that can be divided evenly only by 1 and itself. 2, 5, 7, 13 are prime numbers.
Answer:
\(5^2\times7\times13\).
\(3^2\times13\).
Step-by-step explanation:
Prime number: The number which have only two factors 1 and itself is called prime number .
A.\(5^2\times7\times13\)
The given number is the product of 5,5 ,7 and 13.
5 is a prime number because it has only two factors 1 and 5.
7 is a prime number because it has only two factors 1 and 7.
13 is a prime number because it has only two factors 1 and 13.
Hence, the number shows as a product of prime numbers in exponential form.
B.\(7^2\times24\)
The number is the product of \(7^2 and 24\).
7 is a prime number because it has only two factors 1 and itself.
24 is not prime number because it has more than two factors.
Hence, the number does not shows as product of prime numbers in exponential form.
C.\(3^2\times13\)
The number is the product of \(3^2 and 13\)
3 is a prime number because it has two factors 1 and 3.
13 is a prime number because it has two factors 1 and 13.
Hence, the number shows as the product of prime number in exponential form.
D.\(4\times5^3\)
The number is the product of 4 and \(5^3\)
5 is a prime number because it has two factors 1 and 5.
4 is not a prime number because it has more than two factors.
Hence, the number does not shows as the product of prime numbers in exponential form.