Which of the following shows a number as a product of prime numbers in exponential form? Choose all that apply. 5^2 7 13 7^2 24 3^2 13 4 * 5^3

Verified Answer :

A and C, because prime numbers are numbers that can be divided evenly only by 1 and itself. 2, 5, 7, 13 are prime numbers.

Answer:

\(5^2\times7\times13\).

\(3^2\times13\).

Step-by-step explanation:

Prime number: The number which have only two factors 1 and itself is called prime number .

A.\(5^2\times7\times13\)

The given number is the product of 5,5 ,7 and 13.

5 is a prime number because it has only two factors 1 and 5.

7 is a prime number because it has only  two factors 1 and 7.

13 is a prime number because it has only two factors 1 and 13.

Hence, the number shows as a product of prime numbers in exponential form.

B.\(7^2\times24\)

The number is the product of \(7^2 and 24\).

7 is a prime number  because it has only two factors 1 and itself.

24 is not prime number because it has more than two factors.

Hence, the number does not shows as product of prime numbers in exponential form.

C.\(3^2\times13\)

The number is the product of \(3^2 and 13\)

3 is a prime number because it has two factors 1 and 3.

13 is  a prime number because it has two factors 1 and 13.

Hence, the number shows as the product of prime number in exponential form.

D.\(4\times5^3\)

The number is the product of 4 and \(5^3\)

5 is a prime number because it has two factors 1 and 5.

4 is not a prime number because it has more than two factors.

Hence, the number does not shows as the product of prime numbers in exponential form.