If you are solving y 2+2y=48 by completing the square, the next line would be
What number will make y^2 + 2y + __ a perfect square?
Take coefficient of y, divide by 2, then square it = (2/2)^2 = 1
So add 1 to both sides, since y^2 + 2y + 1 = (y + 1)^2
y^2 + 2y + 1 = 49
For this case we have the following equation:
\(y ^ 2 + 2y = 48\)
By completing squares we have:
Step 1:
Add \((\frac {b} {2}) ^ 2\) on both sides:
\(y ^ 2 + 2y + 1 = 48 + 1\)
Step 2:
We rewrite the equation:
\((y + 1) ^ 2 = 49\)
Step 3:
We solve the equation:
\(y = \pm \sqrt {49} -1\\y = \pm7-1\)
Solutions:
\(y = 6\\y = -8\)
Answer:
the next line would be:
\(y ^ 2 + 2y + 1 = 48 + 1\)