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Answered

How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?

6Li + N₂ 2Li₃N


0.013 moles


0.04 moles


0.08 moles


0.16 moles


0.48 moles

Verified Answer :

diene

For every 2 moles of Li3N, you need 1 mole of N2
so for 0.08 mol Li3N, you need 0.04 moles N2

So 0.04moles of N2 is required.

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