Answer:
Step-by-step explanation:
The given equation is:
\(\sqrt{1-cos^2{\theta}}=-sin{\theta}\)
Taking the Left hand side of the above equation, we get
=\(\sqrt{1-cos^2{\theta}}\)
=\(\sqrt{sin^2{\theta}}\) (Because \(sin^2{\theta}+cos^2{\theta}=1\))
=\({\pm}sin{\theta}\)
Thus, \(\sqrt{1-cos^2{\theta}}=-sin{\theta}\) is true.
Now, since \(sin{\theta}\) is negative, therefore it terminates in the third and the fourth quadrant because in third and fourth quadrant,\(sin{\theta}\) is negative.
