Answer:
43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.
Explanation:
\(Moles (n)=Molarity(M)\times Volume (L)\)
Moles of NaCl = n
Volume of NaCl solution = 500.0 mL = 0.500 L
Molarity of the NaCl solution = 1.500 M
\(n=1.500 M\times 0.500 L=0.75 mol\)
Mass of 0.75 moles of NaCl:
0.75 mol × 58.5 g/mol=43.875 g
43.875 grams of NaCl are required to make 500.0 ml of a 1.500 M solution.
