Tanya drove 3 1/2 hours and used 1/3 tank of gas.


For how long could Tanya drive using​ 1/2 ​tank of gas?


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Answer: \(5\frac{1}{4}\ hours\)


Step-by-step explanation:

Given: Tanya drove car in \(\frac{1}{3}\) tank of gas=   \(3\frac{1}{2}\) hours \(=\frac{7}{2}\) hours

Tanya drove car in a full tank of gas = \(\frac{\frac{7}{2}}{\frac{1}{3}}=\frac{7}{2}\times3=\frac{21}{2}\) hours

Tanya drove car in \(\frac{1}{2}\) tank of gas=\(\frac{21}{2}\times\frac{1}{2}=\frac{21}{4}=5\frac{1}{4}\ hours\)

Hence, Tanya drove \(5\frac{1}{4}\ hours\)car in \(\frac{1}{2}\) tank of gas.