Answer:
\(m\angle GHE=49^{\circ}\)
Step-by-step explanation:
We have been given a paper airplane in which \(ABCD\cong EFGH\).
Since \(ABCD\cong EFGH\), therefore, by the definition of congruence corresponding angles of both quadrilaterals will be equal.
\(m\angle BAD=m\angle FEH\)
\(m\angle B=m\angle F\)
\(m\angle BCD=m\angle FGC\)
\(m\angle CDA=m\angle GHE\)
We know that all interior angles of quadrilateral add up-to 360 degree, so we can set an equation as:
\(m\angle BAD+m\angle B+m\angle BCD+m\angle CDA=360^{\circ}\)
\(m\angle 131^{\circ}+90^{\circ}+90^{\circ}+m\angle CDA=360^{\circ}\)
\(m\angle 311^{\circ}+m\angle CDA=360^{\circ}\)
\(m\angle 311^{\circ}-311^{\circ}+m\angle CDA=360^{\circ}-311^{\circ}\)
\(m\angle CDA=49^{\circ}\)
Therefore, the measure of angle GHE is 49 degrees.
