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What is an equations of the line that passes through (3, -1) and is parallel to y = -4x 1? give your answer in slope-intercept form.

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slope of a line  y = -4x+ 1 is -4. Slope of required line = slope of y = -4x +1 = -4. By slope point form, (y - y1) = m(x - x1). [ (x1,y1) = ( 3, -1) . m = -4].  y - (-1) = -4(x - 3). y + 1 = -4x + 12. y = -4x + 11. So equation of required line is: y = -4x + 11. 

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