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  • 17-12-2016
  • Physics
Answered

A cheetah accelerates from rest at a rate of 5.4 m/s2. How far has the cheetah gone after 1.8 seconds?

Verified Answer :

JohnES
JohnES JohnES
  • 17-12-2016

Us the usual formula,

\(s=\frac{1}{2}at^2=0.5\cdot5.4\cdot1.8^2=8.748\ m\)

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Anonymous Anonymous
  • 17-12-2016

S = ut + 1/2 at^2 . u=0(since cheetah starts from rest). S = 0 + 1/2 at^2. S= 1/2 5.4(1.8)^2 = 8.748m.

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