Answer: \(\dfrac{1}{18}\)
Step-by-step explanation:
Given : Daniel has 1 blue pencil and 5 yellow pencils in his backpack.
Then, the probability of selecting a blue pencil :-
\(\dfrac{\text{Number of blue pencil}}{\text{Total pencil}}\\\\=\dfrac{1}{1+5}=\dfrac{1}{6}\)
He also has 2 pink erasers, 4 tan erasers, and 3 gray erasers in his backpack.
Then, the probability of selecting a gray eraser :-
\(\dfrac{\text{Number of gray erasers}}{\text{Total erasers}}\\\\=\dfrac{3}{2+4+3}=\dfrac{3}{9}\\\\=\dfrac{1}{3}\)
Since both the event are independent of each other.
Then, the probability that he will select a blue pencil and a gray eraser will be :-
\(\dfrac{1}{6}\times\dfrac{1}{3}=\dfrac{1}{18}\)
Hence, the probability that he will select a blue pencil and a gray eraser \(=\dfrac{1}{18}\)
