A candy store makes a 9-pound mixture of gummy candy, jelly beans, and hard candy. The cost of gummy candy is $2.00 per pound, jelly beans cost $3.00 per pound, and hard candy costs $3.00 per pound. The mixture calls for two times as many gummy candy pieces as jelly beans. The total cost of the mixture is $23.00. How much of each ingredient did the store use?

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calculista calculista · Answer 1 · 2018-10-09T17:10:40-04:00

Let

x--------> the amount of gummy candy in pounds

y--------> the amount of jelly beans in pounds

z--------> the amount of hard candy in pounds

we know that

$x+y+z=9$ --------> equation $1$

$2x+3y+3z=23$ --------> equation $2$

$x=2y$ --------> equation $3$

Substitute equation $3$ in equation $1$ and equation $2$

$[2y]+y+z=9$ -----> $3y+z=9$ ------> equation $4$

$2[2y]+3y+3z=23$ -----> $7y+3z=23$ ------> equation $5$

using a graphing tool ------> Solve the system of equations

see the attached figure

the solution is the point $(3,2)$

$z=3\ pounds\\y=2\ pounds$

Find the value of x

$x=2y$

$x=2*2=4\ pounds$

therefore

the answer is

the amount of gummy candy is $4\ pounds$

the amount of jelly beans is $2\ pounds$

the amount of hard candy is $3\ pounds$