So let's work through this. There are 15 + 4 + 1 + 30 tiles, making a total of 50 tiles. The likelihood of the first being red is \(\frac{15}{50}\), since there are 15 red tiles out of the total 50 tiles. Now you have one less tile in the bag, so you have a total of 49 left. Now the chance of pulling out a green one is \(\frac{30}{49}\), since there are 30 green tiles, and only 49 left in the bag. Now you have 48 tiles left. There are only 4 blue tiles, so the likelihood of drawing a blue is \(\frac{4}{48}\). Multiply all these fractions together, \(\frac{15}{50}*\frac{30}{49}*\frac{4}{48} = \frac{90}{5880} = \frac{3}{196}\). This is D.
D. \(\frac3{196}\)
