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I really need help please!


What is the simplified expression for \(\frac { 3^{-4}*2^{3}*3^{2} }{ 2^{4}*3^{-3} }\)

A\(\frac{3}{2}\)
B\(\frac{3^{2} }{2^{2}}\)
C\(\frac{ 3^{2}}{2}\)
D\(\frac{ 2^{4}}{3}\)

Verified Answer :

Simple...

you have: \(\frac{ 3^{-4}* 2^{3}* 3^{2} }{ 2^{4}* 3^{-3} }\)

Multiply it out-->>

\(\frac{8}{9}\)÷\(\frac{16}{27}\)

=\(\frac{3}{2}\) (A)

Thus, your answer.

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