Answered

  1. The ordered pairs model an exponential function, where j is the function name and e is the input variable.

{(1, 10), (2, 50), (3, 250), (4, 1250)}


What is the function equation in sequence notation?


Enter your answer in the box.

je=_______


  1. The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.

What function equation represents the population of the pack of wolves after t years?


f(t)=88(1.025)^t


f(t)=88(0.025)^t


f(t)=88(2.5)^t


f(t)=88(1.25)^t


  1. Ramon bought a bicycle for $478. The value of the bicycle is expected to decrease at a rate of 6.5% each year.

What function equation represents the value of the bicycle after t years?


f(t)=478(1.065)^t


f(t)=478(0.935)^t


f(t)=478(6.5)^t


f(t)=478(0.065)^t

Verified Answer :

Answer:    Hi. I am sorry if this is a late answer, but here are the answer's I have. I just took the test so I am pretty sure these are correct:

#1.

2(5^e)

#3.

B)  f(t)=478(0.935)^t

I am so sorry but I don't have the answer for question #2. I hope you figure it out or someone else can help you. I hope I helped.  Good Luck!

Answer:

1)  \(j=2(5)^e\)

2) option A

3)  option B

Step-by-step explanation:

1)  Given: The ordered pairs model an exponential function, where j is the function name and e is the input variable.

{(1, 10), (2, 50), (3, 250), (4, 1250)}

Let an exponential function \(y=ab^x\)

Now, put (1,10) ⇒10=ab      .....(1)

put (2,50) ⇒\(50=ab^2\)     ....(2)

divide (1) and (2)

we get b=5 then put back in (1)

we get 10=a(5)⇒ a=10/5= 2

therefore the required function is \(y=2(5)^x\)

For j is the function name and e is the input variable

the function is  \(j=2(5)^e\)

2) Given: The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.

To find: What function equation represents the population of the pack of wolves after t years

solution : \(f(t) = P(1+r)^t\)

where P-population , r- growth rate , t -time

putting value we get, \(f(t) = 88(1+0.025)^t\)

                \(f(t) = 88(1.025)^t\)

therefore, option A is correct

3) Given: Ramon bought a bicycle for $478. The value of the bicycle is expected to decrease at a rate of 6.5% each year.

To find: What function equation represents the value of the bicycle after t years.

solution : \(f(t) = P(1-r)^t\)

where P-population , r- decay rate , t -time

putting values we get,   \(f(t) = 478(1-0.65)^t\)

                                        \(f(t) = 478(0.935)^t\)

therefore, option B is correct