A person weighing 500 N climbs 3 m. How much power is needed to make the climb in 5 sec?
Answer: The power needed by the person is 300 W
Explanation:
Power is defined as the ratio of rate of work done by an object.
Mathematically,
\(P=\frac{W}{t}\)
where,
P = power of the person
W = work done by the person = \((F\times d)\)
F = force applied by the person = 500 N
d = displacement of the person = 3 m
t = time taken = 5 sec
Putting values in above equation, we get:
\(P=\frac{F\times d}{t}\\\\P=\frac{500N\times 3m}{5sec}\\\\P=300W\)
Hence, the power needed by the person is 300 W