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A line has a slope of 1/4 and passes through the point (0.2, 4/5) find the value of b, the y-intercept.

Verified Answer :

ZavierL

The general formula of a line is y=mx+b
since we know the slope is 1/4, y=1/4x+b
so to find b, the y-intercept, we substitute the point (0.2, 4/5)
\(\frac{4}{5}\) =  \(\frac{1}{4}\) (0.2) + b
b=0.75. 
Hence Y intercept is 0.75 or \(\frac{3}{4}\)

onyebuchinnaji

The value of the y-intercept of the line is 0.75.

The given parameters;

  • slope of the line, = \(\frac{1}{4}\)
  • points on the line = (0.2, 4/5)

The general equation of line is given as;

y = mx + b

where;

m is the slope of the line

b is the y-intercept

The y-intercept b is calculated by substituting the given parameters as shown below;

y = mx + b

\(\frac{4}{5} = \frac{1}{4}(0.2) + b\\\\\)

0.8 = 0.05 + b

b = 0.8 - 0.05

b = 0.75

Thus, the value of the y-intercept of the line is 0.75.

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