\(X + y = 12\)
\(3x = 2y + 6\)
In the first equation, multiply the first equation by 2.
In the second equation, move the 2y to the left.
\(2x+2y=24\)
\(3x-2y=6\)
Add the two equations to eliminate y and solve for x:
\(5x+0=30\)
\(x=6\)
Plug-in the the value of x in the either original equation to solve for x.
I will use the first original equation because it is simpler than the second.
\(X + y = 12\)
\(y=6;x=6\)
