Answer: The radical equivalent of \(27^{\frac{2}{3}\) = 9.
Step-by-step explanation:
Since we have given that
\(27^{\frac{2}{3}\)
We need to find the radical equivalent to it
We will use the "exponential law" .
\((a^m)^\frac{1}{n}=a^{\frac{m}{n}}\)
So, it becomes,
\([(27)^\frac{1}{3}]^2\\\\=[(3^3)^{\frac{1}{3}}]^2\\\\=[3^\frac{3}{3}]^2\\\\=3^2\\\\=9\)
Hence, the radical equivalent of \(27^{\frac{2}{3}\) = 9.
