Answer:
1/x
Step-by-step explanation:
\((x^{-3})^\frac{1}{3}\)
To simplify this we need to apply property of exponents
(a^m ) ^n = a^mn
Multiply inside exponent with outside exponent
\((x^{-3})^\frac{1}{3}\)
\(x^{-3}*^\frac{1}{3}\)
-3 times 1/3 becomes -1
\(x^{-1}\)
a^-m = 1/a^m
So \(x^{-1}= \frac{1}{x^1} = \frac{1}{x}\)