Does it matter what two factors you select to complete a factor tree? And tell me how you knew
No, just keep factoring until you cannot factor any further.
example:
90
.^
910
^....^
3325
I could also start with 156, 330 or whatever. but the final answer will still be
2335 = 23^2*5.
No. as long as you factor out until you get to numbers that can't be factored you're fine. For example if you're factoring out 36 you can start with 18 and 2 or 12 and 3 or 4 and 9 and still end up with the factorization of 2•2•3•3