For f(x)=2x+1 and g(x)=x^2-7, find (f-g)(x)

Verified Answer :

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(f-g)(x)=2x+1-(x^2-7)



(f-g)(x)=2x+1-x^2+7


(f-g)(x)= -x^2+2x+8

Answer:

The required answer is: \(-x^2+2x+8\)

Step-by-step explanation:

We have been given the two function:

\(f(x)=2x+1\)

And \(g(x)=x^2-7\)

We have to find (f-g)(x):

\((f-g)(x)=f(x)-g(x)\)

\((2x+1)-(x^2-7)\)

\(2x+1-x^2+7\)

\(-x^2+2x+8\)

We will get the quadratic expression after the prescribed operation been applied.

Hence, the required answer is: \(-x^2+2x+8\)