For f(x)=2x+1 and g(x)=x^2-7, find (f-g)(x)
I hope this helps you
(f-g)(x)=2x+1-(x^2-7)
(f-g)(x)=2x+1-x^2+7
(f-g)(x)= -x^2+2x+8
Answer:
The required answer is: \(-x^2+2x+8\)
Step-by-step explanation:
We have been given the two function:
\(f(x)=2x+1\)
And \(g(x)=x^2-7\)
We have to find (f-g)(x):
\((f-g)(x)=f(x)-g(x)\)
\((2x+1)-(x^2-7)\)
\(2x+1-x^2+7\)
\(-x^2+2x+8\)
We will get the quadratic expression after the prescribed operation been applied.
Hence, the required answer is: \(-x^2+2x+8\)