Answer:
\(\text{The integral factors are }(3x-4)(2x+15)\)
Step-by-step explanation:
Given the quadratic polynomial
\(6x^2+37x-60\)
we have to find the integral factors of the above polynomial.
\(\text{The polynomial is }6x^2+37x-60\)
By splitting middle-term, the polynomial can be written as
\(6x^2+37x-60\)
\(6x^2-8x+45x-60\)
Taking 2x common from first two terms and 15 from last two terms.
\(2x(3x-4)+15(3x-4)\)
Taking (3x-4) common
\((3x-4)(2x+15)\)
which are required factors of given polynomial.
Hence, option 1 is correct.
