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What is the general form of the equation for the given circle?


x2 + y2 − 8x − 8y + 23 = 0


x2 + y2 − 8x − 8y + 32 = 0


x2 + y2 − 4x − 4y + 23 = 0


x2 + y2 + 4x + 4y + 9 = 0

What is the general form of the equation for the given circle? x2 + y2 8x 8y + 23 = 0 x2 + y2 8x 8y + 32 = 0 x2 + y2 4x 4y + 23 = 0 x2 + y2 + 4x + 4y + 9 = 0 class=

Verified Answer :

HomertheGenius

Coordinates of the center:  ( 4, 4 )
The radius:  r = 7 - 4 = 3
The equation of a circle:
( x - 4 )² + ( y - 4 )² = 3²
x² - 8 x + 16 + y² - 8 y + 16 = 9
x² + y² - 8 x - 8 y + 32 - 9 = 0
Answer:
A ) x² + y² - 8 x - 8 y + 23 = 0

Answer:

A ) x² + y² - 8 x - 8 y + 23 = 0

Step-by-step explanation:

hope i helped

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