Hello!
Find the Energy of the Photon by Planck's Equation, given:
E (photon energy) =? (in Joule)
h (Planck's constant) = \(6.626*10^{-34}\:J * s\)
f (radiation frequency) = \(8*10^{12}\:Hz\)
Therefore, we have:
\(E = h*f\)
\(E = 6.626*10^{-34}*8*10^{12}\)
\(E = 53.008*10^{-34+12}\)
\(E = 53.008*10^{-22}\)
\(\boxed{\boxed{E = 5.3008*10^{-21}\:Joule}}\end{array}}\qquad\checkmark\)
I Hope this helps, greetings ... DexteR! =)
