Verified Answer :
p=ma^2+ba+c, so you have
118=m35^2+35b+c
218=m45^2+45b+c
563=m55^2+55b+c so solving
I get m=49/40
b=-88
c=13579/8 so its
p=(49/40)a^2-88a+(13579/8)
Answer:
\(p=\dfrac{49}{40}a^2-88a+\dfrac{13579}{8}\)
Step-by-step explanation:
Let premium p for age of a , (p,a)
# An insurance company charges a 35-year old non-smoker an annual premium of $118 for a $100,000 term life insurance policy.
(35,118)
# An insurance company charges a 45-year old non-smoker an annual premium of $218 for a $100,000 term life insurance policy.
(45,218)
# An insurance company charges a 55-year old non-smoker an annual premium of $563 for a $100,000 term life insurance policy.
(55,563)
Let quadratic model be p=Aa²+Ba+C
Substitute the points into equation
- For point, (35,118)
\(118=35^2A+35B+C\)
\(118=1225A+35B+C\) -------------(1)
- For point, (45,218)
\(218=45^2A+45B+C\)
\(218=2025A+45B+C\) -------------(2)
- For point, (55,563)
\(563=55^2A+55B+C\)
\(563=3025A+55B+C\) -------------(3)
Solve system of equation and find out A, B and C using calculator.
\(A=\dfrac{49}{40},B=-88,C=\dfrac{13579}{8}\)
Quadratic model:
\(p=\dfrac{49}{40}a^2-88a+\dfrac{13579}{8}\)