An insurance company charges a 35-year old non-smoker an annual premium of $118 for a $100,000 term life insurance policy. The premiums for 45-year olds and 55-year old no smokers are $218 and $563, respectively. Write a quadratic model for the premium p as a function of age a.

Verified Answer :

p=ma^2+ba+c, so you have

118=m35^2+35b+c
218=m45^2+45b+c
563=m55^2+55b+c so solving

I get m=49/40
b=-88
c=13579/8 so its
p=(49/40)a^2-88a+(13579/8)

Answer:

\(p=\dfrac{49}{40}a^2-88a+\dfrac{13579}{8}\)

Step-by-step explanation:

Let premium p for age of a , (p,a)

# An insurance company charges a 35-year old non-smoker an annual premium of $118 for a $100,000 term life insurance policy.

(35,118)

# An insurance company charges a 45-year old non-smoker an annual premium of $218 for a $100,000 term life insurance policy.

(45,218)

# An insurance company charges a 55-year old non-smoker an annual premium of $563 for a $100,000 term life insurance policy.

(55,563)

Let quadratic model be p=Aa²+Ba+C

Substitute the points into equation

  • For point, (35,118)

\(118=35^2A+35B+C\)

\(118=1225A+35B+C\) -------------(1)

  • For point, (45,218)

\(218=45^2A+45B+C\)

\(218=2025A+45B+C\) -------------(2)

  • For point, (55,563)

\(563=55^2A+55B+C\)

\(563=3025A+55B+C\) -------------(3)

Solve system of equation and find out A, B and C using calculator.

\(A=\dfrac{49}{40},B=-88,C=\dfrac{13579}{8}\)

Quadratic model:

\(p=\dfrac{49}{40}a^2-88a+\dfrac{13579}{8}\)