Answer:
The new volume of the gas is 2 m³
Explanation:
It is given that,
Initial temperature, \(T_1=5\ K\)
Initial volume, \(V_1=1\ m^3\)
Final temperature, \(T_2=10\ K\)
We need to find the new volume. The Charles law gives the relation between the temperature and the volume of the gas.
i.e
\(V\propto T\)
\(\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\)
\(V_2=\dfrac{V_1}{T_1}\times T_2\)
\(V_2=\dfrac{1}{5}\times 10\)
\(V_2=2\ m^3\)
So, the new volume of the gas is 2 m³. Hence, this is the required solution.
