Answer:
Drain A \(54\ min\)
Drain B \(21.6\ min\)
Step-by-step explanation:
Let
x------> the time in minutes
y-----> the volume of the pool in gallons
we know that
The equation that represent the situation is equal to
\(y=mx\)
solve for x
\(x=y/m\)
Drain A
\(x=y/m\)
In this case we have
\(m=2\frac{gal}{min}\)
\(y=108\ gal\)
substitute
\(x=108/2=54\ min\)
Drain B
\(x=y/m\)
In this case we have
\(m=5\frac{gal}{min}\)
\(y=108\ gal\)
substitute
\(x=108/5=21.6\ min\)
