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evaluate 3X^2-14X-49/X-7
the quotient of the equation is __X+__

Verified Answer :

I hope this helps you

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Answer:

\(3x+7\)

Step-by-step explanation:

\(\frac{3x^2-14x-49}{x-7}\)

before dividing this fraction , lets factor the numerator

\(3x^2-14x-49\)

Product is -49 and sum is -14, lets break the middle term using factors

\((3x^2+7x)+ (-21x-49)\)

Take out GCF from each group

\(x(3x+7)-7(3x+7)\)

\((3x+7)(x-7)\)

Now we replace the factors in the numerator

\(\frac{(3x+7)(x-7)}{x-7}\)

We have (x-7) at the top and bottom , so we cancel it out

\(3x+7\)

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