Consider the trinomial 9x2 + 21x + 10. What value is placed on top of the X? What value is placed on the bottom of the X? What is the factored form of 9x2 + 21x + 10?
Answer: 1) Value is placed on top of the X =90
2) Value is placed on the bottom of the X =21
3) Factored form will be (3x+5)(3x+2)
Step-by-step explanation:
Since we have given that
\(9x^2 + 21x + 10\)
As we know the quadratic form :
\(ax^2+bx+c=0\)
1) Value is placed on top of the X is given by
\(a\times c=9\times 10=90\)
2) Value is placed on the bottom of the X is given by
\(b=21\)
3) Factorised form:
We will use "Split the middle term":
\(9x^2 + 21x + 10\\\\=9x^2+15x+6x+10\\\\=3x(3x+5)+2(3x+5)\\\\=(3x+2)(3x+5)\)
Hence, Factored form will be
(3x+5)(3x+2)