suppose a population is carrying a condition controlled by two alleles R (dominant) and r (recessive). if the frequency of the r allele is 15% and the frequency of the R allele is 85%. what will be the frequency of the RR genotype ,assuming evolution is not occuring?

Verified Answer :

jaehee

I believe it's 72.25%

Answer:

Frequency of the RR \(= 72.25\)%

Explanation:

Given -

R is the dominant allele and r is the recessive allele.

The frequency of the r allele is \(15\)%\(= 0.15\)

The frequency of the R allele is \(85\)%\(= 0.85\)

As per Hardy Weinberg's equation-

\(p = 0.85\)

\(q = 0.15\)

Also, evolution is not occurring is the basic assumption of Hardy Weinberg's principle.

Frequency of the RR genotype is equal to \(p^{2}\)

Substituting the value of "p" we get

\(p^{2} = 0.85^{2} \\= 0.7225\\= 72.25\)