suppose a population is carrying a condition controlled by two alleles R (dominant) and r (recessive). if the frequency of the r allele is 15% and the frequency of the R allele is 85%. what will be the frequency of the RR genotype ,assuming evolution is not occuring?
Answer:
Frequency of the RR \(= 72.25\)%
Explanation:
Given -
R is the dominant allele and r is the recessive allele.
The frequency of the r allele is \(15\)%\(= 0.15\)
The frequency of the R allele is \(85\)%\(= 0.85\)
As per Hardy Weinberg's equation-
\(p = 0.85\)
\(q = 0.15\)
Also, evolution is not occurring is the basic assumption of Hardy Weinberg's principle.
Frequency of the RR genotype is equal to \(p^{2}\)
Substituting the value of "p" we get
\(p^{2} = 0.85^{2} \\= 0.7225\\= 72.25\)