What's the answer ????????
there is a right triangle in a cone :)we will use pythagorean theorem ;?^2+(7.41)^2=16^2?^2=16^2-(7.4)^2if we both side square root;\(\sqrt{?^2}= \sqrt{16^2-(7.4)^2} \\ ?= \sqrt{16^2-(7.4)^2}\)So the answer is 4th option :)