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The graph in the figure shows the variation of the electric potential V(x) (in arbitrary units) as a function of the position x (also in arbitrary units). Which of the choices below correctly describes the orientation of the x-component of the electric field along the x-axis?

AEx is positive from x = -2 to x = 0, and negative from x = 0 to x = 2.
BEx is negative from x = -2 to x = 0, and positive from x = 0 to x = 2.
CEx is negative from x = -2 to x = 2.
DEx is positive from x = -2 to x = 2.

The graph in the figure shows the variation of the electric potential V(x) (in arbitrary units) as a function of the position x (also in arbitrary units). Which class=

Verified Answer :

okpalawalter8

We have that the orientation of the x-component of the electric field along the x-axis is give by

Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2 ,

Option B

Electric field along the x-axis

Generally, The co-ordinates of the cartesian  axis in this context shows the electric field along each axis.

Therefore, for the electric field along the x-axis we consider the x axis components .

Judging from the graph we see that

Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2 ,

does justice to describing the orientation of the x-component of the electric field along the x-axis.

For more information on Cartesian  visit

https://brainly.com/question/9410676

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