Log5(x+6) - log5(x+2) = log5x
x = 2Use the log rules to condense the left side. log5 ((x+6)/(x+2))=log5xlog 5 will cancel on both sides. (x+6)/(x+2)=x Solving you get x=2 and x =-3. The domain of log is x >0 so the -3 is an extraneous solution.
