Answered

What is the solution set of the following equation?


4/5x^2=2x-4/5

  1. {1, 2}
  2. {1, 1/2}
  3. {2, 1\2}

Verified Answer :

apologiabiology

multiply both sides by 5
4x^2=10x-4
divide both sides by 2
2x^2=5x-2
minus 5x from both sides and add 2 to both sides
2x^2-5x+2=0
use quadratic formula
for
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)

given
2x^2-5x+2=0
a=2
b=-5
c=2
x=\(\frac{-(-5)+/- \sqrt{(-5)^2-4(2)(2)} }{2(2)}\)
x=\(\frac{5+/- \sqrt{25-16} }{4}\)
x=\(\frac{5+/- \sqrt{9} }{4}\)
x=\(\frac{5+/- 3}{4}\)
x=(5+3)/4 or (5-3)/4
x=8/4 or 2/4
x=2 or 1/2

3rd option is correct

sierra3324

Answer:

{2, 1\2}

Explanation:

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