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which rule describes the transformation that was used to form parallelogram A'B'C'D'

which rule describes the transformation that was used to form parallelogram A B C D class=

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The answer would be c because you went left 10 and when you go left its always negative.Then you went down 3 .When going down its also negative

Transformation involves changing the position of a shape

The transformation rule is: \((x-10,y-3)\)

From the attachment, we have:

\(A = (4,7)\)

\(A' = (-6,4)\)

The translation rule from ABCD to A'B'C'D' is calculated as follows:

\((x,y) = A' - A\)

This gives:

\((x,y) = (-6,4) - (4,7)\)

Rewrite as:

\((x,y) = (-6- 4,4-7)\)

\((x,y) = (-10,-3)\)

Hence, the transformation rule is:

\((x-10,y-3)\)

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