solve for g : 2g-m=5-gh
\(2g-m=5-gh\ \ \ \ |add\ "m"\ and\ "gh"\ to\ both\ sides\\\\2g+gh=5+m\\\\g(2+h)=5+m\ \ \ \ |divide\ both\ sides\ by\ (2+h)\\\\\boxed{g=\frac{5+m}{2+h}}\)
\(2g-m=5-gh\\ 2g+gh=m+5\\ g(2+h)=m+5\\ g=\frac{m+5}{h+2}\\\\ h ot=-2\)
