taeleur
Answered

In two or more complete sentences, explain how to solve the cube root equation,

∛x-1 +2=0

Verified Answer :

W0lf93

Answer: x = -1

WORKINGS

We are to solve the cube root equation, ∛x – 1 + 2 = 0

Solve like terms; subtract 1 from 2 to get -1 (-1 + 2 = +1)
Therefore, ∛x + 1 = 0

Move +1 to the right side of the equation, since it does not contain the variable to solve for. 

∛x + 1 = 0
Subtract 1 from both sides of the equation
∛x + 1 – 1 = 0 – 1
∛x = -1

Cube both sides of the equation in order to remove the radical on the left side
(∛x)^3 = (-1)^3
x = -1

calculista

we have

\(\sqrt[3]{x} -1+2=0\)

Step 1

Solve like terms

\(\sqrt[3]{x}+(-1+2)=0\)

\(\sqrt[3]{x}+(1)=0\)

Step 2

Subtract 1 from both sides of the equation

\(\sqrt[3]{x}+1-1=0-1\)

\(\sqrt[3]{x}=-1\)

Step 3

Cube both sides of the equation in order to remove the radical on the left side

\((\sqrt[3]{x})^{3}=(-1 )^{3} \\ x=-1\)

therefore

the answer is

\(x=-1\)

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