What is 528−−√+63−−√528+63 in simplest radical form?
Answer: \(13\sqrt{7}\)
Step-by-step explanation:
In the simple radical form there are no square root is remain to find.
Since, the given expression,
\(5\sqrt{28} + \sqrt{63}\)
\(5\sqrt{4\times 7} + \sqrt{9\times 7}\)
\(5\sqrt{4} \times \sqrt{7} + \sqrt{9}\times \sqrt{7}\)
\(5\times 2 \times \sqrt{7} + 3\times \sqrt{7}\)
\(10 \sqrt{7} + 3\sqrt{7}\)
\((10 + 3)\sqrt{7}\)
\(13\sqrt{7}\)
Since, we do not need to find further square root of 7.
Thus, the required radical form of \(5\sqrt{28} + \sqrt{63}\) is \(13\sqrt{7}\).
Answer:
\(13\sqrt{7}\)
Step-by-step explanation:
\(5\sqrt{28} +\sqrt{63}\)
To simplify the given expression we simplify each radical
\(5\sqrt{28} = 5\sqrt{4*7} = 5*2\sqrt{7} =10\sqrt{7}\)
\(\sqrt{63} = \sqrt{9*7} =3\sqrt{7}\)
\(5\sqrt{28} +\sqrt{63}\)
\(10\sqrt{7}+3\sqrt{7}\)
\(13\sqrt{7}\)