First lets review property of exponents:
\((a^m)^n = a^{m*n}\)
\((\frac{a}{b})^m = \frac{a^m}{b^m}\)
\(a^m *a^n = a^{m+n}\)
\(a^{-m} = \frac{1}{a^m}\)
\(a^0 = 1\)
Ok now we can do this problem:
\((2^{8(-2)} * 3^{(-5)(-2)}*1^{-2}) \frac{3^{(-2)(4)}}{2^{3(4)}} * 2^{28}\)
\((2^{-16} *3^{10}*1)(\frac{3^{-8}}{2^{12}})*2^{28}\)
\((2^{-16 -12+28}) (3^{10 -8})\)
\((2^0)(3^2)\)
\(= 9\)
