Answer:
The radius of the probe from the center of Venus is \(9.08\times10^{6}\ m\).
Explanation:
Given that,
Gravitational force\(F_{g} = 2.58\times10^{3}\ N\)
Mass of Venus \(M= 4.87\times10^{24}\ kg\)
Mass of probe m= 655 kg
Suppose we find the radius of the probe from the center of Venus
We need to calculate the radius
Using gravitational force
\(F_{g}=\dfrac{GmM}{r^2}\)
Put the value into the formula
\(2.58\times10^{3}=\dfrac{6.67\times10^{-11}\times655\times4.87\times10^{24}}{r^2}\)
\(r^2=\dfrac{6.67\times10^{-11}\times655\times4.87\times10^{24}}{2.58\times10^{3}}\)
\(r=\sqrt{\dfrac{6.67\times10^{-11}\times655\times4.87\times10^{24}}{2.58\times10^{3}}}\)
\(r=9.08\times10^{6}\ m\)
Hence, The radius of the probe from the center of Venus is \(9.08\times10^{6}\ m\).
