The projectile will take about 9 s to reach the highest point in its path.
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Further explanation
Acceleration is rate of change of velocity.
\(\boxed {a = \frac{v - u}{t} }\)
\(\boxed {d = \frac{v + u}{2}~t }\)
where:
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
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Let's recall Range of Projectile formula as follows:
\(\boxed{ R = \frac{ v_o^2 \sin 2\theta}{g} }\)
where:
R = range of projectile ( m )
v₀ = initial speed of projectile ( m/s )
θ = angle of projection
g = gravitational acceleration ( m/s² )
Let us now tackle the problem!
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Given:
initial vertical component of speed of projectile = u_y = 90 m/s
initial horizontal component of speed of projectile = u_x = 49 m/s
gravitational acceleration = g = 9.80 m/s²
Asked:
time taken to reach the highest point = t = ?
Solution:
As we know that the final vertical component of speed of projectile at the highest point is 0 m/s , therefore:
\(v_y = u_y - gt\)
\(0 = 90 - 9.8t\)
\(90 = 9.8t\)
\(t = 90 \div 9.8\)
\(t \approx 9 \texttt{ s}\)
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Learn more
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
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Answer details
Grade: High School
Subject: Physics
Chapter: Kinematics
