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Balance this redox reaction occurring in acidic media:

Cr2O7[2-](aq) + Cl[-](aq) <---> Cr[3+] (aq) + Cl2(g)

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syed514

Add 7 water atom to the right hand side to adjust the quantity of oxygen. Increase Cr(+3) by two to adjust the quantity of Cr. Duplicate Cl-by two to adjust the quantity of chlorine molecules. 
Cr2O7[2-](aq) +2 Cl[-](aq) < - >2 Cr[3+] (aq) + Cl2(g)+7H2O 
Presently adjust that charges. 
you have - 4 charges on the left hand side, while +18 charges on the right hand side, there for include 14H+ the left hand side to adjust the charges 
Cr2O7[2-](aq) +2 Cl[-](aq)+14H+ < - >2 Cr[3+] (aq) + Cl2(g)+7H2O 
take note of that the oxidation number of hydrogen in water is +1

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