Answer:
\(\sqrt[5]{(\frac{y^3}{x^2})}\)
Step-by-step explanation:
\((\frac{x^3\times y^{-2}}{xy})^{\frac{-1}{5}}\)
Now we will use the quotient rule of exponent which is given by
\(\frac{x^a}{x^b}=a^{a-b}\)
Using this property, we get
\(({x^{3-1}\times y^{-2-1}})^{\frac{-1}{5}}\)
On simplifying, we get
\(({x^{2}\times y^{-3}})^{\frac{-1}{5}}\)
Now, use the property, \(x^{-a}=\frac{1}{x^a}\)
\((\frac{x^2}{y^3})^{\frac{-1}{5}}\)
Now, we can use the rule \(x^{1/a}=\sqrt[a]{x}\)
\((\frac{y^3}{x^2})^{\frac{1}{5}}\\\\=\sqrt[5]{(\frac{y^3}{x^2})}\)
